thinking about a CRX.
02-15-2005, 03:59 PM
#31
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Originally Posted by ucipreludebebe
i don't like the way the crx looks........ i dunno why, u pretty stuck on the idea of a crx?
Yeah, lightweight owns > *.
My car feels like a go kart and goes around corners really fast and feels stable doing it.
02-15-2005, 10:35 PM
#33
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hey jaje...
Originally Posted by IrradiatedKitty
I say if you're gonna get one.. and swap the engine anyway, go for the Si, the main reason the HF weighs the least is because the suspension components.
Originally Posted by jaje
a 2,000lb car with 200whp will out run a 300hp 3,000 lb car...that's b/c it takes 4 times the power to move something that weighs only twice as much
f = ma
a = f / m
We'll make a constant.
double m:
F = 2ma
what's F?
a = F / 2m = f / m
remember f was the original force necessary to give acceleration a:
f / m = F / 2m
F = 2mf / m
F = 2f
Double the mass, double the force necessary to maintain a given acceleration a. However, I don't doubt your experience, so.... am I missing something?
02-16-2005, 08:29 AM
#34
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Originally Posted by WiLL
oakland....thats one good deal man...wanna sell it to me
:thumbup:
howd you find it?
:thumbup: howd you find it?
02-16-2005, 08:18 PM
#36
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Originally Posted by augy
Let's ask Dr. Newton:
f = ma
a = f / m
We'll make a constant.
double m:
F = 2ma
what's F?
a = F / 2m = f / m
remember f was the original force necessary to give acceleration a:
f / m = F / 2m
F = 2mf / m
F = 2f
Double the mass, double the force necessary to maintain a given acceleration a. However, I don't doubt your experience, so.... am I missing something?
f = ma
a = f / m
We'll make a constant.
double m:
F = 2ma
what's F?
a = F / 2m = f / m
remember f was the original force necessary to give acceleration a:
f / m = F / 2m
F = 2mf / m
F = 2f
Double the mass, double the force necessary to maintain a given acceleration a. However, I don't doubt your experience, so.... am I missing something?
i came across this watching a good Discovery show called Junkyard Wars and they were doing the physics of drag racing (that was the premise of that episode)
02-16-2005, 09:50 PM
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Originally Posted by jaje
the premise is based on the assumption that you have to hold all other factors equal and this includes drive train layout and even tire size...heavier more powerful cars require wider tires to put down the power as opposed to a lighter less powerful car...with this scenario increased weight uniformily with power will not net you same acceleration and you will have to in effect quadruple the power in order to net same acceleration
i came across this watching a good Discovery show called Junkyard Wars and they were doing the physics of drag racing (that was the premise of that episode)
i came across this watching a good Discovery show called Junkyard Wars and they were doing the physics of drag racing (that was the premise of that episode)
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